To convert from the usual ppmv units to ppm mass, multiply by the ratio of the molar weight of CO 2 to that of air, i.e. If we would do it each day for the next 10 years, only 4.7 kg a day would be necessary per each person you can imagine it as two small-sized bricks a day.ĭoing all this in small portions constantly, this entire job is achievable without extraordinary effort. Carbon dioxide concentrations have varied widely over the Earths 4.54 billion year history. Physical workers usually do not carry more than 4,000 kg per 8-hr shift, so one person would need at least 5 days to carry out just the lifting work. Therefore, we need 7.5 billion of such trucks, in order to go back to the safe Carbon level. Amount enough to fill a 20-ft container truck! If we would relate that amount to standard cement bags, each of us would need to take care of 687 (25 kg) bags. Since each mole is 126.737 grams, you multiply 3.5 mols by 126.737 grams, giving you 443.58 grams. This gives a molar mass of 126.737 g/mol. If we understand that there are 7.5 billion people on this planet, and we task each person to take care of his or her own portion, each person would need to sequester around 17,165 kg of Carbon. First, you can calculate the molar mass of FeCl2 by adding the molar masses of Fe (55.845 g/mol) and 2 atoms of Cl (2 times (35.446 g/mol). Saying 128.74 Giga-tonnes of carbon sounds quite abstract and does not mean much. Convert MG/M3 to PPM Carbon monoxide CO, M 28.01 g/mol Carbon dioxide CO2, M 44.01 g/mol Chlorine Cl2, M 70.9 g/mol Formaldehyde CH2O, M. The current global average concentration of CO 2 in the atmosphere is (0.04) 421 ppm as of May 2022. It is one of several greenhouse gases in the atmosphere of Earth. In order to go back to the safe level of 350 ppmv, we would need to sequester 128.74 GtC In Earth's atmosphere, carbon dioxide is a trace gas that plays an integral part in the greenhouse effect, carbon cycle, photosynthesis and oceanic carbon cycle. At that time, the CO2 level was around 280 ppmv, or, in other words, since pre-industrial times, human influence has added 130.28, which equates to 278.24 Giga tonnes of Carbon ((410.28-280) * 2.1357 GtC per ppmv ). Stoichiometric Equation Determine the moles of 'NaHCO'3' by dividing the given mass of 'NaHCO'3' by its molar mass, then determine moles of 'CO'2' by multiplying times the mole ratio with 'CO'2' in the numerator, then multiply times the molar mass of 'CO'2'. We will take the year 1800 as the comparison point for pre-industrial CO2 concentration in the atmosphere. Let’s now consider how much CO2 or Carbon we have added since the Industrial Revolution and how much carbon we need to sequester, in order to reach what is considered the stable level of 350ppmv. This will give us 0.0623240117 m% CO2.įurthermore, multiplying Earth’s atmosphere 5.137 × 10^15 tonnes * 0.0623240117 m% CO2, we will see that the total weight of CO2 in the atmosphere is ~3,208 Gt CO2.Īs the carbon content in carbon dioxide is 27.3%, that also means that each 1 ppmv (part per million of volume) of the atmosphere weighs approximately 2.1357 Gt of Carbon.Īs I said, current CO2 levels have reached the dangerously high 410.28 ppmv, and it is said that if we reach 450ppmv there is a 50% chance that we will reach 2C, which many call the point of no return. Now, we can calculate the following: 0.041028% (CO2 atmosphere volume) * 28.971 g/mole (average molar mass of dry air) / 44.0087 g (CO2). If we take the highest measured concentration of CO2 as 410.28 ppmv, the percentage content would be equal to 0.041028%. We can calculate that 1 mole of CO2 has a weight of 44.0087 grams Mol is is defined as the amount of a chemical substance that contains as many representative particles (atoms, molecules, ions, electrons, or photons) as there are atoms in 12 grams of carbon-12 therefore, one mole has 12.011 g C, and 1 gram of carbon has 0.083257 mole. ).Let’s start from the mass of the Earth atmosphere, which is 5.137 × 10^15 tonnes
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